Question

In a class 10 boys are more than the girls. from this form an equation and draw a graph for this.​

Answer 1

Answer:

Let number of boys be x.

Number of girls be y.

Given that total number of student  is 10 so that

x+y=10

Subtract y both side we get

x=10–y

Plug y=0,5,10 we get

x=10–0=10

x=10–5=5

x=10–10=0

Therefore, the required points are (0,10),(5,5),(10,0).

Given that If the number of girls is 4 more than the number of boys

So that

y=x+4

Plug x=−4,0,4, and we get

y=−4+4=0

y=0+4=4

y=4+4=8

Therefore, the required points are (−4,0),(0,4),(4,8).

Since the point of intersection in the above graph is (3,7),

Therefore, the number of boys is 3 and the number of girls is 7.

Step-by-step explanation:

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