Question

In a class 30% of the students play tennis only and 40% of the students play squash only. 20 students do not play any of these games and 40 play both games.

Find:
1-No. of students in the class
2-tennis students
3-Squash students

koi help kare degs mera

Answer 1

$<b><marquee behavior ="alternate">SOLUTION:</marquee>$

$\textbf{Q1: No. of students in the class}$

Let the no. of students be x

Students playing only tennis = 30% of x

$= \frac{30}{100} \times x \\ \\ = \frac{3x}{10}$

Students play squash only = 40% of x

$= \frac{40}{100} \times x \\ \\ = \frac{4x}{10}$

Therefore,

$\frac{3x}{10} + \frac{4x}{10} + 20 + 40 = x \\ \\ \frac{3x}{10} + \frac{4x}{10} - \frac{x}{1} = - 60 \\ \\ \frac{3x + 4x - 10x}{10} = - 60 \\ \\ \frac{3x}{10} = 60 \\ \\ x = \frac{60 \times 10}{3} \\ \\ x = 200 \\ \\ total \:number\:of\:students \: are = 200$

$\textbf{Q.2: Number of tennis students}$

$= \frac{3 \times 200}{10} \\ \\ = 60 \\ \\ =60 + 40 \\ \\ number\:of\:tennis\:students=100$

$\textbf{Q.3: Number of Squash students}$

$= \frac{4 \times 200}{10} \\ \\ = 80 + 40 \\ \\number\:of\:squash\: students = 120$

Answer 2

Answer:

1-Total students:200

2-students who only play tennis:100

3-students who only play squash:120