in a class of 48 students the number of boys is 3 upon 5 of the number of girls find the number of boys and girls in the class
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total strength is 48
no of boys is x
no of girls is y
so we have
x+y=48...........
and
x =3/5y
so we have
x+y=48
x÷y=3/5
_______
2x=60
x=30
therefore
x+y=48
30+y=48
y=18
no of boys is x
no of girls is y
so we have
x+y=48...........
and
x =3/5y
so we have
x+y=48
x÷y=3/5
_______
2x=60
x=30
therefore
x+y=48
30+y=48
y=18
gaurangtripathi2:
but answer is not coming
Answered by
13
Hope this will help u
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