Question

in a class of 48 students the number of regular student in more than the number of a regular student. Had two irregular student been regular and the product of the number of two type of student be 380 find the number of each type of student

Answer 1

Answer:

12

Step-by-step explanation:

number of students=48

regular students be x

irregular students=48-x

when 2 irregular became regular

reg students=x+2

num of irreg students=48-x-2=46-x

product of both is 380

(x+2)*(46-x)=380

middle term break

(x-36)(x-8)=0

so x can be

36 or 8

as reg students are more than irre students so x=36

number of irregular=48-x=48-36=12

b)determination

Answer 2

the number of each type of student is 12