In a class of 48 students , the number of regular students is more than the number of irregular students . Had two irregular students been regular , the product of the number of two types of students would have been 380.
(a) Find the number of each type of students in the class.
(b) suggest on more value, other than regularity, that a student must possess.
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- number of students=48
- regular students be x
- irregular students=48-x
when 2 irregular became regular
- reg students=x+2
- num of irreg students=48-x-2=46-x
- product of both is 380
(x+2)*(46-x)=380
- middle term break
(x-36)(x-8)=0
so x can be
36 or 8
as reg students are more than irre students so x=36
number of irregular=48-x=48-36=12
b)determination
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