Question

In a class of 500 children, the ratio of the number of successors and the number of failures is 3:2. Had 50 more students passed, what would have been the ratio of successors and failures?​

Answer 1

Step-by-step explanation:

In the beginning, there were 2x, 3x and 5x students in the three classes, where x is a constant of proportionality. In each section, 40 students were added.

There are 2k+40, 3k+40 and 5k+40 students in each section.

Given, 2k+40:3k+40:5k+40=4:5:7

3 K+4 02 K+4 0=541 0 K+2 0 0=1 2 K+1 6 0⇒2 K=4 0⇒K=2 0∴  Originally the total number of students was 2×2 0+3×2 0+5×2 0=2 0 0

Answer 2

Answer:

5:6

Step-by-step explanation:

let the no of succesors be 3x and failures be 2x

BTP,

=

2x+3x= 500

5x=500

x=100

So, successors= 2x =(2*100) = 200

      failures = 3x = 3*100 = 300

if 50 more student passed,

numbers of succesors

200+50= 250

the ratio of succesors and failures now

= 250:300

= 5:6