Question

In a class of 60 students, 25 students play cricket, 20 students play tennis and 10 students play both. Then the number of students who play neither cricket nor tennis

Answer 1

number of total students = 60
number of students play cricket = 25
number of students play tennis = 20
number of students play both = 10
total number of students which play games =
25+20+10 = 55
number of students play nothing = 60-55 = 5
Hence, 5 students neither play cricket nor tennis .
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Answer 2

Answer:

Number of students who play neither tennis nor cricket is 25.

Step-by-step explanation:

We are given,

Universal set U that is collection of all students, n( U ) = 60

Set C be the collection of  student play cricket , n( C ) = 25

Set T be the collection of student play tennis , n( T ) = 20

number of students who play both game , n( C ∩ T ) = 10

We need to find number student who don't play any game

we know that,

n ( C ∪ T ) = n( C ) + n( T ) - n( C ∩ T ) = 25 + 20 - 10 = 45 - 10 = 35

Number student who don't play any game = n( U ) - n( C ∪ T ) = 60 - 35

                                                                       = 25

Therefore, Number of students who play neither tennis nor cricket is 25.