In a class of 60 students,25 students play cricket and 20 students play baseball. If is fout that 10 students play both games. Find the number of students who play at leat one game
Answers
Step-by-step explanation:
no of students U = 60.
student who play cricket C = 25.
student who play tannis T = 20.
students who plays both of them = 10
so student who plays neither of them = 60 - ( 25+ 20 - 10 ) = 60 - 35 = 25
Given :
In a class of 60 students,25 students play cricket and 20 students play baseball and 10 students play both games
To find :
Find the number of students who play at least one game
solution :
Let C and T denote the number of students play Cricket and Tennis, respectively. And U denotes the total number of students in a class.
n(C) = 25, n(T) = 20 and n(∪)= 60
n(C ∪ T) = n(C) + n(T) - n(C ∩ 7)
= 25 + 20 - 10
= 45 - 10
= 35
The number of students who play neither Cricket nor Tennis
= n(C ∩ T) = n(∪) - n(C ∪ T)
= 60 - 35
= 25
=> 25 students who play at least one game