Question

In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is :
(A) 1/6
(B) 1/3
(C) 2/3
(D) 5/6

Answer 1

Answer:

option is (A)1/6

Step-by-step explanation:

hope the explanation in the pic helps you

PLEASE MARK MY ANSWER AS THE BRAINLIEST

Answer 2

Step-by-step explanation:

i)let students selected for NCC be A

let students selected for NSS be B

NCC or NSS be n(AUB)

NCC and NSS both be n(AintersectionB)

U be 60

n(AUB)= n(A)+n(B)-n(A intersection B)

=30+32-24

=62-24

=38

n(AUB)'=n (U)-n(AUB)

=60-38

=22

Therefore, answer is

i)38 students

ii)22 students

Hope it helps.

If you like my answer plz mark my answer as brainliest and thank me