Question

In a class of 80 students, 60% participate in games and the rest do not. The average weight of

the former group is 5% more than that of the latter. If the average weight of all the students is 51
1/2 kg​, then what is the average weight (in kg) of the former group?​

Answer 1

The average weight of the former group would be 54.075 kg.

Step-by-step explanation:

The average weight of all the students = $51\frac{1}{2}$ kg.

The average weight of the former group is 5% more than that of the later.

The average weight of the former group = $51\frac{1}{2}$ + ( 5% of $51\frac{1}{2}$ )

=  $\frac{103}{2}+(0.05\times \frac{103}{2})$

= $\frac{103}{2}+2.575$

= 54.075

The average weight of the former group would be 54.075 kg.

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