Question

in a class there are 6 boys and 40 girls, find the probability that the students chosen at random is : (I) a boy (ii) a girl

Answer 1

Step-by-step explanation:

1. the probability that the student choosen at random be a boy be E1

number of possible outcomes =40+6=46

number of favourable outcomes=6

p(E1)=6/46

=3/23

2. the probability that the student choosen at random be a girl be E2

number of possible outcomes=46

number of favourable outcomes=40

p(E2)=40/46

=20/23

Answer 2

Solution:

Boys, n(B) = 6

Girls, n(G) = 40

Total students, n(T) = Boys + Girls = 6 + 40 = 46 students

Probability Formula =>

P(A) = n(E)/n(S)

where,

P(A) = Probability of an event “A”

n(E) = Number of favourable outcomes

n(S) = Number of events in the sample space

Now, we have to chose students at random

(I) a boy

We need to find the probability of selecting a boy randomly from total students.

Probability of selecting a boy at random, P(B) = n(B)/n(T) =  6/46 = 3/23

(I) a girl

We need to find the probability of selecting a girl randomly from total students.

Probability of selecting a girl at random, P(G) = n(G)/n(T) =  40/46 = 20/23