In a closed system a(s)----2b(g)+ 3c(s) if the partial pressure of c is doubled then partial pressure of b will be
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Answer:
❤ 1/2√2 to its initial value
Explanation:
kp = pb^2 × pc^3 ....... 1
after changing partial pressure
kp = Pb^2 × (2pc)^3 ........ 2
change in pc given but change in pb not given so
assume pb becomes Pb
since kp is a constant and function of only temperature
from 1 and 2
Pb^2 = pb^2 /8
Pb^2 = pb^2 /8 Pb = 1/2√2 pb
since capital Pb is final partial pressure
and small pb is initial pressure
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