Chemistry, asked by Aniketojha820, 10 months ago

In a closed system a(s)----2b(g)+ 3c(s) if the partial pressure of c is doubled then partial pressure of b will be

Answers

Answered by kailashmeena123rm
42

Answer:

❤ 1/2√2 to its initial value

Explanation:

kp = pb^2 × pc^3 ....... 1

after changing partial pressure

kp = Pb^2 × (2pc)^3 ........ 2

change in pc given but change in pb not given so

assume pb becomes Pb

since kp is a constant and function of only temperature

from 1 and 2

Pb^2 = pb^2 /8

Pb^2 = pb^2 /8 Pb = 1/2√2 pb

since capital Pb is final partial pressure

and small pb is initial pressure

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