Question

In a coil of resistance of 10 ohm the induced current developed by changing magnetic flux"

Answer 1

Answer:

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Answer 2

Answer:

Induced current,  $i = \frac{\frac{-d\phi }{dt} }{10}$

Explanation:

since we know that according to the faraday law of electromagnetic induction , when magnetic flux is changing with respect to time then  it causes an induced emf ,mathematically it is written as

$emf = \frac{-d\phi }{dt}$......................(1)

assuming number of turns 1

we know that this emf is equal to the induced current times resistance.

so, emf = i x r.......................(2)

we have resistance r = 10 ohm

So, induced current,

using (1) and (2) we get

$i = \frac{\frac{-d\phi }{dt} }{10}$