Question

In a college, 200 students are randomly selected. 140 like tea, 120 like coffee and 80 like both tea and coffee. How many students like at least one of the beverages?

Answer 1

200-140=60

200-120=80

80+60=140

140-80=60

ans is 60

Answer 2

Answer: 180

Step-by-step explanation:

Given : In a college, 200 students are randomly selected. 140 like tea, 120 like coffee and 80 like both tea and coffee.

Let T denotes the number of students like tea and C be the event that students like coffee.

Then,  n(T)=140 , n(C)=120  ,  n(T∩C) =80

Now, n(T∪C) = n(T)+n(C)-n(T∩C)

n(T∪C) = 140+120-80

n(T∪C) = 180

Hence, the number of people ike at least one of the beverages =180