Question

In a college , 200 students are randomly selected , 154 like tea , 97 like coffee, and 80 like both tea and coffee … how many students like atleast one of the beverage?

Answer 1

Step-by-step explanation:

the ans is 171 students .... hope it helps

Answer 2

Answer :- 180

Step-by-step explanation:

Given : In a college, 200 students are randomly selected. 140 like tea, 120 like coffee and 80 like both tea and coffee.

Let T denotes the number of students like tea and C be the event that students like coffee.

Then, n(T)=140 , n(C)=120 , n(T∩C) =80

Now, n(T∪C) = n(T)+n(C)-n(T∩C)

n(T∪C) = 140+120-80

n(T∪C) = 180

Hence, the number of people ike at least one of the beverages =180

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