Question

In a combustion reaction of an organic compound, 2.5 mol of CO2 were produced. What volume would it occupy at STP (273K, 1bar) ?

Answer 1

Explanation:

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Answer 2

Answer:

Explanation:

We know that =Pv=Nrt V=Nrt/p=2.5×8.341×273/1×10⁵=5674.3×10-⁵= 0.0567letre = 56.u ml