Question

In a committee. 50 people speak French, 20 speak Spanish and 10 speak
Spanish and French. How many speak at least one of these two language
​

Answer 1

Answer:

LET

• F the set of people in the committee who speak FRANCEH.
• S the set of people in the committee who speak SPANISH.

n(F)=50, n(S)=20, n(SuF)=10

therefore,

n(SuF)=n(F)+n(S)-n(SuF)

=50+20-10

=70-10

=60

therefore,60 people speak at least one of these two languages...

☝️i hope its helpful to you...☝️

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

☯ Given :

• Number of People speak french n(A) = 50
• Number of People speak spanish n(B) = 20
• Number of People speak both french and spanish n(A $\cap$ B) = 10

$\rule{200}{1}$

☯ To Find :

We have to find number of people who speaks at least one language.

$\rule{200}{1}$

☯ Explanation :

We know that,

$\large{\implies{\boxed{\boxed{\sf{n(AUB) = n(A) + n(B) - n(A \cap B)}}}}}$

→ Put Values in above formula

$\sf{\rightarrow n(AUB) = 50 + 20 - 10} \\ \\ \sf{\rightarrow n(AUB) = 70 - 10} \\ \\ \sf{\rightarrow n(AUB) = 60} \\ \\ \Large{\implies{\boxed{\boxed{\sf{n(AUB) = 60}}}}} \\ \\ \sf{\therefore \: Number \: of \: people \: who \: speaks \: at \: least}\\\sf{one \: language \: is \: 60.}$