Math, asked by shreyasbhai, 11 months ago

In a competition, the amount of prize money for the first position is 5 by 3 of that for the second
position. The prize amount for the third position is 4 by 7 of that for the second position. If the
total amount of prize money is 36,800, find the prize amounts for each of the three positions.​

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Answers

Answered by Anonymous
7

Step-by-step explanation:

let us assume

first position is A

second is B

and third is C

ATQ

A:B=5:3

B:C=7:4

now a:b:c

5:3

7:4

a:b:c is 35:21:12

total prize is 36800 then

A prize money is

35/68×36800=18941.1765

lly B

21/68×36800=11364.7059

and C

12/68×36800=6494.117

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