Math, asked by adityashibu666, 7 months ago

In a competition, the amount of prize money for the first position is 5 by 3 of that for the second position. The prize amount for the third position is 4 by 7 of that for the second position. If the total amount of prize money is 6,800, find the prize amounts for each of the three positions

Answers

Answered by TanishqGodha
23

Let the amount for the second position be x.

Then prize for first position = 5x /3

Prize for second position = x

Prize for third position = 4x / 7

Since total prize money is 6800 ,

5x / 3 + x + 4x / 7 = 6800

( 5x * 7 + 21 * x + 4x * 3 ) / 21 = 6800

( 35x + 21x + 12x ) / 21 = 6800

68x / 21 = 6800

x = 6800 / 68 * 21

x = 2100

Therefore the prizes are :-

First prize = 5x / 3. = 3500

Second prize = x = 2100

Third prize = 4x / 7 = 1200

PLEASE MARK BRAINLIEST

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