in a competitive examination there where 60 questions the correct answer would carry two marks and for incorrect answer one marks would be subtracted Yashwant had attempt all the questions and he got total 90 marks then how many questions he got wrong
Answers
Answer:
Let No of Correct answers be x
Let No. of wrong answers be y
Let No. of Unattempted question be z
Given that He had attempted all the questions that means z = 0
Now, Total number of questions (x+y+z)=60
⇒x+y=60 _________ (i)
No. of marks awarded for each correct answers = 2
Total Number of marks for correct answers = (No. of correct answers)*(Marks awarded for each correct answer)
Total Number of marks for correct answers = x*2=2x
Similarly No. of marks awarded for each wrong answers = -1
Similarly No. of marks awarded for each wrong answers = (No. of wrong answers)*(Marks awarded for each wrong answer)
Total Number of marks for wrong answers = y*(-1)=-y
Total marks 90 =
(No. of marks awarded for each correct answers) + (Total Number of marks for wrong answers)
⇒ 90 = 2x-y _________ (ii)
From (i) we get y = 60-x
Substituting Value of y above in (ii)
⇒90 = 2x-(60-x)
⇒90 = 2x-60+x
⇒90 = 3x-60
⇒3x=150
⇒x=50
Now,
⇒y = 60 - x
⇒y=60-50
⇒y=10
Therefore, x=50 & y=10
killer
ace killer
the answer for your question
detailed answer
yashwant attempted all questions in the exam
so from that questions some may be right and some may be wrong
so let the correct answers be X and incorrect be y
so total questions were 60 so
now the marking scheme for correct answer was 2 marks
and if the answer is incorrect then 1 mark will be deducted so it will be -1
so
in this exam he go 90 marks
so the equation will be
therefore we get
so in eq i we have
so
substitute the value of y in eq ii
so we get
2x-(60+x)=90
therefore
2x-60+x=90
3x=90+60
3x=150
X=150/3
x= 50
substitute value of x in eq i
50+y=60
y=60-50
y=10
hence the no. of correct answer yashwant attempted were 50 and incorrect answers were 10