In a compound , atoms of element Y form ccp lattica amd those of element X occupy 2/3rd of tetrahedral voids . The formula of the compund will be a. X4Y3 b.X2y3 c.X2Y d.X3Y4
Answers
Answer:
See below.
Explanation:
The atoms of Y are occupying the lattice points of simple Cubic Closed Packed lattice.
Therefore, atoms of Y = ( 1 / 8 ) * 8 + ( 1 / 2 ) * 6 = 4
X has occupied 2/3 of octahedral voids.
The number of tetrahedral voids = 2 * 4 = 8
Number of X atoms = 2/3 * 8 = 16 / 3
Formula of compound : X4Y3
Answer:
a. X4Y3
Explanation: number of atoms present in ccp lattice = 4 = number of atoms in y
number of tetrahedral voids in ccp lattice = 8
they given x occupied 2/3 of tetrahedral voids = 2 x 8 /3 = 16 / 3 = number of atoms in x
so the formula is = X 16/3 Y 4
multiply both numerator and denominator of 4 with 3 then it becomes 12/3
then the denominators of x and y will cancel
then the final formula would become X16 Y12
by simplyfying we get the formula as X4Y3