In a compound FeCl2, the orbital angular momentum of the last electron in its cation and magnetic moment (in Bohr Magneton ) of this compound is?
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Hey Dear,
◆ Answer -
Magnetic moment of Fe2+ = 2.45 BM
Magnetic moment of Fecl2 = 4.89 BM
◆ Explaination -
1) For Fe2+ cation,
No of free electrons = 2
Orbital magnetic moment is calculated by -
OMM = √(2×3) = 2.45 BM
2) For FeCl2 compound,
No of free electrons = 4
Magnetic moment is calculated by -
MM = √(4×6) = 4.89 BM
Hope this helps you. Thanks for asking..
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