In a compound nitrogen atoms n make cubic close packed lattice and metal atoms m occupy one third of the tetrahedral voids present.determine the formula of the compound formed by m and n
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n=4
m=1/3×8
therefore, 8/3:4
FORMULA= M8N12=M4N6=M2N3
m=1/3×8
therefore, 8/3:4
FORMULA= M8N12=M4N6=M2N3
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