in a conductor 6.25*10^16 electrons flow from its end A to B in 2 sec find the current flowing through the conductor
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as there 1 coulomb in 6.25*10^18 electrons
thus we have charge = 10^-2
therefore current in the conductor is given by q*t
hence I = 10^-2*2
i.e. 0.02 ampere
thus we have charge = 10^-2
therefore current in the conductor is given by q*t
hence I = 10^-2*2
i.e. 0.02 ampere
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