Question

in a conductor, 6.25x10 (power 16) electrons flow from its end A to B in 2 s. Find the current flowing through the conductor. (e = 1.6 * 10 (-19 power) C

Answer 1

No. of electrons = 6.25×10^16
Charge on each electron= 1.6 × 10^-19 C

So total charge Q
= 6.25×10^16 × 1.6 ×10^-19
= 6.25 × 1.6 × 10^-3
= 10 × 10^-3
= 10^-2 C

Time t= 2s
so current I = Q/t
= (10^-2)/2
=1/100×2=1/200
= 0.005 A
= 5× 10^-3 A
= 5 mA

Thus your answer is 5 mA.

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Answer 2

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