Question

in a consistently of 80500 voters 60% cast their votes and in a straight contest between two candidates the winner obtained 2600 votes more than his opponent.what is percentage of votes cast in favour of each candidates?​

Answer 1

Answer:

sorry friend I don't know a answer sorry sorry sorry sorry

Answer 2

Step-by-step explanation:

No. of voters who casrs their votes=60%of80500=48300.

And,

Let.candidate A get x votes.

Then, the candidate B gets x+2600 votes.

Now, x+(x+2600)=48300

2x+2600=48300

2x=(48300-2600)=45700

X=45700/2=22850

So,the% of votes secured by A=22850/48300*100=43.30% (approx)

And, B secures (100-43.30)%=66.70%.