Question

In the figure of AABC, DE || AB, AD = 2x, DC = x + 3, BE = 2x - 1 and CE = x.
Then, find the value of x.
x+3
2x - 1E XC

Answer 1

Answer:

x = 3/5

Step-by-step explanation:

As DE║AB , CD/AB = CE/BE ( BPT )

⇒ x+3 / 2x = x/2x - 1

⇒(x + 3)(2x - 1) = 2$x^2$

⇒2$x^2$ + 5x - 3 = 2$x^2$

⇒5x - 3 =0

⇒ x = 3/5