In a container there is mixture of 385 ml of milk and 1155 ml of water. If 15% of the mixture is taken out and replaced with same amount of milk, then find the percentage of milk in new mixture??
Answers
Total quantity of mixture= Milk+Water = 385 ml +1155ml
=1540 ml
15% mixture was taken out,
taken out quantity of mixture= 1540×15/100ml
231 ml.
According the sum , same amount of milk was added again,
that means 231 ml milk was added, so new quantity of milk in mixture was = (385+231)ml=616ml
therefore,
now percentage of milk in new mixture= (616÷1540×100)ml= 40 ml
Ans:-- percentage of milk in new mixture is 40%
Answer:
36.25%
Step-by-step explanation:
total quantity of mixture = milk + water
= 385 + 1155
= 1540 ml
milk% in the mixture = 385÷ 1540 × 100
= 0.25 × 100
= 25%
= 25 / 100
Ratio of milk = 1 / 4
when 15% of mixture is taken out i.e
15% of 1540
= 15/ 100 × 1540
= 231 ml
1540 - 231 = 1309 ml remaining quantity
If we remove any quantity from mixture but the ratio of contents remain same. So in 1309 ml milk ratio is 1 / 4
Quantity of milk in 1309 ml = 1 / 4 × 1309 = 327.25 ml
Now , in this quantity again 231 ml milk is added
i.e. 327.25 + 231 = 558.25 ml
558.25 ÷ 1540 × 100
= 0.3625 × 100
= 36.25 %