in a convex lens u= -25 f=10 find v and nature of the image formed
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Explanation:
Given that, f=10cm
a) When u=−9.5cm
v
1
−
u
1
=
f
1
⇒
v
1
=
10
1
−
9.8
1
−
98
−0.2
⇒v=−490cm
So, ⇒m=
u
v
=
−9.8
−490
=50cm
So, the image is erect and virtual.
b) When u=−10.2cm
v
1
−
u
1
=
f
1
⇒
v
1
=
10
1
−
−10.2
1
=
0.2
102
⇒v=510cm
So, m=
u
v
=
−9.8
510
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