Question

in a cooperative society , the number of men is thrice the number of women. 29 women and 16 men more joined this society. now the number of men is double the number of women. How many women's are there first?

Answer 1

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Answer 2

The number of women at first would be 42.

Step-by-step explanation:

Let the women's original count in the society be x

So,

Number of men in original = 3x

After 29 women and 16 men together became part of this society,

The number of women = x + 29

The number of men = 3x + 16

It is given that,

The new count of men is double the count of women. So,

(3x + 16) = 2(x + 29)

⇒ (3x + 16) = 2x + 58

⇒ (3x - 2x) = (58 - 16)

∵ x = 42

Thus, the women's count at first was 42.

Learn more: Find the number

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