Question

In a copper vessel we pour 20 gm of hot water at 80°C . Now 100 gm of cold water at 10°C is added to the vessel. Find the final temperature of mixture if vessel weighs 50 gm.​​

Answer 1

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Heat lost by water to change it is temperature from 60℃ to 30℃=ms△T.

=40×4.2×30

=5040J.

Heat gained by water,

=50×4.2×10

=2100J.

Heat gained by vessel,

= Heat capacity ×10

Heat lost by hot water,

= heat lost by cold water + heat gained by vessel.

∴ Heat gained by vessel,

=5040−2100

=2940.

Heat capacity×10=2940

Heat capacity =2940/10

=294J/℃

Explanation:

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