Question

In a cricket ground, player A throws a ball of 150g in horizontal direction up to 15 m and player B throws a ball of 300 g in vertical direction upto same distance. Find the ratio of work done on a ball by gravitational force in both the cases. ​

Answer 1

Answer:

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Explanation:

Maximum horizontal distance, R = 100 m

The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45°, i.e., θ = 45°.

The horizontal range for a projection velocity v, is given by the relation:

R = (u2 Sin 2θ) / g

100 = (u2 Sin 900 )/ g

u2 / g = 100 ….(i)

The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H.

Acceleration, a = –g

Using the third equation of motion:

v2 – u2 = -2gH

H = u2 / 2g = 100 / 2 = 50 m