Question

in a cricket match a batsman hit a boundary 12 times out of 80balls he plays . further ,if he plays one ball more , what will be probability that i) he hits a boundary ii) he does not hit aboundary

Answer 1

probability that he hit boundary=12/81
probability that he does not hit the boundary=69/81

Answer 2

batsman hit the boundary = 12 times
total balls = 80
probability of he hit boundary = 12÷80 = 0.15
now the balls that batsman not hit are = 80-12 =68 times
so probability of he doesn't hit boundary = 68÷80 = 0.85
thanks May it is helpful to you