in a cricket match a batsman hit a boundary 12 times out of 48 balls he play find the probability that he does not hit a boundary in the next ball
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here you go ☆☆
to find probability:-
total outcomes = 48
no. of times he hit boundary = 12
no. of times he do not hit boundary( E ) = 36
so, p( E ) = 36/48 => 3/4
probability of not hitting boundary next time = 37/49
hope it helps:)
to find probability:-
total outcomes = 48
no. of times he hit boundary = 12
no. of times he do not hit boundary( E ) = 36
so, p( E ) = 36/48 => 3/4
probability of not hitting boundary next time = 37/49
hope it helps:)
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