Question

In a cricket match, a batsman hits a boundary 6 times out of 90 balls he plays.
Find the probability that he (i) hit a boundary (ii) did not hit a boundary.
We have, guys please give me answer with solution please ​

Answer 1

Heya, here is ur answer:

Total balls: 90

Times hit boundary: 6

Therefore, probability of getting a boundary= 6/90

Total balls: 90

Times hit boundary: 6

Therefore, number of times he did not hit boundary= 90-6

                                                                                      = 84

Therefore, probability of did not hit a boundary= 84/90

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