Question

In a Cricket match, a batsman hits a boundary 6 times out of 30 balls he
plays. Find the probability that he did not hit a boundary.
​

Answer 1

Given :

In a Cricket match, a batsman hits a boundary 6 times out of 30 balls he plays

To Find :

Probability that he didn't hit a boundary

Solution :

Method - 1 :

Probability of hitting a boundary :

No. of possible outcomes to hit a boundary = 6

Total no. of possible outcomes = 30

$\sf \longrightarrow \dfrac{Number\ of\ possible\ outcomes }{Total\ number\ of\ possible\ outcomes}$

$\sf \longrightarrow \dfrac{6}{30}$

$\sf \longrightarrow\ \dfrac{1}{5}$

Probability of not hitting a boundary :

No. of possible outcomes not to hot a boundary = 30 - 6 = 24

Total no. of possible outcomes = 30

$\longrightarrow \dfrac{30-6}{30}$

$\longrightarrow \dfrac{24}{30}$

$\longrightarrow\ \dfrac{4}{5}$

Method - 2 :

Method - 2 :Probability of hitting a boundary :

No. of possible outcomes to hit a boundary = 6

Total no. of possible outcomes = 30

$\longrightarrow\ \dfrac{1}{5}$

Probability of not hitting a boundary :  

$\longrightarrow$  1 - Total no. of possible outcomes

$\longrightarrow 1-\dfrac{1}{5}$

$\longrightarrow\ \dfrac{4}{5}$

Answer 2

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Accroding to the question,

Total number of balls = 30

Numbers of baundary = 6

So, number of times batswoman didn't hid the boundary = (30-6)=24

Probability she didn't hit a boundary = 24/30=4/5