Question

In a cricket match, a batsman hits a boundary 8 times out of 40 balls he played. find the probability that he didn't hit a

boundary.​

Answer 1

Answer:

4/5

Step-by-step explanation:

no of times he hit the boundary =8

total no of balls= 40

no of times he didn't hit the boundary= 40-8= 32

therefore, probability of times he didn't hit the boundary= 32/40

= 16/20

=8/10

=4/5

Answer 2

Answer:

4/5

Step-by-step explanation:

Let n(E) is the event that the batsman did not hit a boundary.

Number of balls in which batsman not hit the boundary = Number of ball - Number of ball hit the boundary

n(E) = 40 -8 = 32

Total Number of balls n(S) = 40

Probability = n(E) / n(S) = 32/40 = 4/5