In a cricket match, a batsman hits a boundary 8 times out of 40 balls he played. find the probability that he didn't hit a
boundary.
Answers
Answered by
19
Answer:
4/5
Step-by-step explanation:
no of times he hit the boundary =8
total no of balls= 40
no of times he didn't hit the boundary= 40-8= 32
therefore, probability of times he didn't hit the boundary= 32/40
= 16/20
=8/10
=4/5
Answered by
1
Answer:
4/5
Step-by-step explanation:
Let n(E) is the event that the batsman did not hit a boundary.
Number of balls in which batsman not hit the boundary = Number of ball - Number of ball hit the boundary
n(E) = 40 -8 = 32
Total Number of balls n(S) = 40
Probability = n(E) / n(S) = 32/40 = 4/5
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