Question

① In a cricket match, a batsman hits a boundary 8 times out of 40 balls he played. find the probability that he didn't hit a boundary.
② From the table given in example 2, find the probability of selecting a bag having number of germinated seeds as (i) more than 40 (ii) 49.​

Answer 1

Answer:

1) Batsman did not hit ball = 40-8 = 32

P(batsman did not hit the ball) = 32/40

4/5

Answer 2

Step-by-step explanation:

1) Let n(E) is the event that the batsman did not hit a boundary.

Number of balls in which batsman not hit the boundary = Number of ball - Number of ball hit the boundary

n(E) = 40 -8 = 32

Total Number of balls n(S) = 40

Probability = n(E) / n(S) = 32/40 = 4/5

2) answer for this question is in the above pic

hope it helps