Question

In a cricket match a batsman hits boundary in 20% of the balls he played . find the probability that he did not hit a boundary

Answer 1

He hits the boundary in 20% of balls
 P(hitting boundary) = 20100 = 0.2P (not hitting boundary) = 1-0.2 = 0.8 = 80%

Answer 2

Answer:

Answer is 4/5

Step-by-step explanation:

Given,

Batsman hits 20% boundary he faces.

Find,

Probability that he did not hit the boundary.

Percentage he did not hit the boundary=100%-20%=80%.

Probability =80/100 =4/5

=0.8%