in a cuboid, let a, b and c be the lengths of diagonals drawn on three faces having a corner in common. let d be the length of the largest diagonal that can be drawn in the cuboid. then
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L2+B2 = (39)2 ……………….(1)
L2 + H2 = (40)2……………..(2)
B2 + H2 = (41)2……………..(3)
ADDING ALL THESE EQ-
2(L2+B2+H2) = 4802
L2+B2+H2 = 2401
TAKING ROOTS AT BOTH SIDES WE GET;
DIAGONAL = 49
L2 + H2 = (40)2……………..(2)
B2 + H2 = (41)2……………..(3)
ADDING ALL THESE EQ-
2(L2+B2+H2) = 4802
L2+B2+H2 = 2401
TAKING ROOTS AT BOTH SIDES WE GET;
DIAGONAL = 49
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