Question

In a current carrying conductor,the ratio of electric field and the current density at a point is called
A) Resistivity
B)Conductivity
C)Resistance
D)Mobility
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Answer 1

Answer: (a) Resistivity

Explanation:

J= 1/rho × E

rho=E/J

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Answer 2

Hence it is called a s resistivity.

Option (A) is correct.

Explanation:

We know that J  = σE  

• Where J = current density
• σ = conductivity
• E= electric field

Also, resistivity ρ =  1/σ

thus,  

J / σ  = E

or  Jρ = E

Therefore , a = ρ

Hence it is called a s resistivity.

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