Question

In a cyclic quadrilateral ABCD, if ∠A-∠C=60°, prove that the smaller of two is 60°.

Answer 1

Step-by-step explanation:

we know that oppositr angles of Cyclic quadrilateral has 180 as sum

so

A+C=180

A-C=60

2A=240

A=120°

then C is 180-120

60°