In a cyclic quadrilateral abcd , if angle a +angle b = 185 and angle b+angle c = 165 find angle d
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∠A + ∠B = 185°
∠A = 185 - ∠B
∠B + ∠C = 165°
∠C = 165 - ∠B
In cyclic quadrilateral opposite angles are supplementary.
=> ∠A + ∠C = 180
185 - ∠B + 165 - ∠B = 180
-2B + 350 = 180
-2∠B = 180 - 350
-2∠B = -170
∠B = -170/-2
∠B = 85°
In cyclic quadrilateral opposite angles are supplementary.
∠B + ∠D = 180
85 + ∠D = 180
∠D = 180 - 85
∠D = 95°
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