Question

In a cyclic quadrilateral abcd m ∠dab = 80 and m ∠bad = 50 find ∠adb

Answer 1

Answer:

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In △ABD, ∠ABD + ∠ADB + ∠DAB = 180° [angle sum property of triangle]

50° + ∠ADB + 60° = 180°

⇒ ∠ADB = 70°

Now, ∠ACB = ∠ABD = 70° [∵ angle in same segment]

Step-by-step explanation:

Solve like this.....

Answer 2

Answer:

dab = 80 and m ∠bad = 50 find ∠adb

Step-by-step explanation:

hope it helps