Question

In a cyclic quadrilateral ABCD, P is the
point of intersection of the diagonals AC
and BD. If angle APB = 64º and angle CBD =
28°, then what is the value of angle ADB?
​

Answer 1

Answer:

36°

Step-by-step explanation:

angles in same segment are equal

<cbd=<cad=28°

<apb=64°

SO<apd=180-64=116°

angle bpcis also 116°

in triangleAPD

angle a+p+x=180

28+116+x=180

x=36 °