In a cyclic quadrilateral,the angles A,B,C and D are (y-10),(y-50),(12x+10) and (x+20) respectively.Find the values of x and y. URGENT please hlp
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we know concept of cyclic quadrilatral
A+C=180 degree
hence
y-10+12x+10=180
12x+y=180---------(1)
and
B+D=180
y-50+x+20=180
x+y=210 ---------(2)
now solve (1) and (2) equation
x=-30/11
and y=2340/11
A+C=180 degree
hence
y-10+12x+10=180
12x+y=180---------(1)
and
B+D=180
y-50+x+20=180
x+y=210 ---------(2)
now solve (1) and (2) equation
x=-30/11
and y=2340/11
Answered by
0
In a cylic quadrilateral, opposite angles are supplementary.
Angle A = (y-10)°
Angle B= (y-50)°
Angle C=(12x+10)°
Angle D=(x+20)°
Angle A + Angle C = 180°
y-10+12x+10=180
y+12x=180
Therefore, y=180-12x----(I)
Angle B + Angle D= 180°
y-50+x+20=180
y+x-30=180
180-12x+x-30=180. (from I)
-11x+150=180
-11x=30
x=-30/11
Therefore, y= 180-12x=180-12(-30/11)
y=180+360/11
y=1980+360/11
y=2340/11
Angle A = (y-10)°
Angle B= (y-50)°
Angle C=(12x+10)°
Angle D=(x+20)°
Angle A + Angle C = 180°
y-10+12x+10=180
y+12x=180
Therefore, y=180-12x----(I)
Angle B + Angle D= 180°
y-50+x+20=180
y+x-30=180
180-12x+x-30=180. (from I)
-11x+150=180
-11x=30
x=-30/11
Therefore, y= 180-12x=180-12(-30/11)
y=180+360/11
y=1980+360/11
y=2340/11
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