In a cylinder radius is doubled and height is half what will be its curved surface area
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Answered by
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Dimensions of the cylinder
radius = r
Height = h
i ) curved surface area
(CSA) = 2πrh----( 1 )
ii ) volume (v) = πr² h ---( 2 )
2 ) if radius doubled and radius
halved then new cylinder
dimensions are
Radius ( R ) = 2r
Height ( H ) = h /2
New CSA = 2 × π × ( 2r ) × h / 2
= 2πrh
Therefore ,
There is no change in csa .
Zero percent change in csa.
New volume ( V ) = π× (2r)² × ( h / 2 )
= 2πr²h
= 2 × v
Therefore ,change in volume is
100%
I hope this
radius = r
Height = h
i ) curved surface area
(CSA) = 2πrh----( 1 )
ii ) volume (v) = πr² h ---( 2 )
2 ) if radius doubled and radius
halved then new cylinder
dimensions are
Radius ( R ) = 2r
Height ( H ) = h /2
New CSA = 2 × π × ( 2r ) × h / 2
= 2πrh
Therefore ,
There is no change in csa .
Zero percent change in csa.
New volume ( V ) = π× (2r)² × ( h / 2 )
= 2πr²h
= 2 × v
Therefore ,change in volume is
100%
I hope this
vinodkumar100880:
It's write or wrong
Answered by
2
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