In a deer park the number of heads and the number of legs of deer and visitors were counted and it was found that there were 39 heads and 132 legs. Find the number of deers and visitors.. solve it using elimination method
Answers
Answer:
There are 12 visitors and 27 deer's
Step-by-step explanation:
let deer be represented by d and visitors represented by v.
deer and visitors have one head each, so d + v = 39
a deer has 4 legs and a visitor has 2 legs, so 4d + 2v = 132
d + v = 39
4d + 2v = 132
d = 39 - v
4(39 - v) + 2v = 132
156 - 4v +2v = 132
-2v = 132 - 156
-2v = -24
v = -24/-2
v = 12
d = 39 - v
d = 39 - 12
d = 27
there are 12 visitors and 27 deer.
to check:
d + v = 39
27 + 12 = 39
39 = 39
4d + 2v = 132
4(27) + 2(12) = 132
108 + 24 = 132
132 = 132
Hope this helps you, Stay home and Stay safe
Answer:
27 - deer, 12 visitors
Step-by-step explanation:
total no of legs = 132
total no of heads = 39
Let x = number of deer and y = number of visitors.
4x + 2y = 132 ---- equation 1
x + y = 39
x = 39-y
4(39-y) + 2y = 132
156 - 2y = 132
2y = 156-32
y=24/2 = 12
substitute value of y in equation 1
4x + 24 = 132
4x = 132-24
x = 108/4
x = 27