Question

In a dihybrid cross (AaBb × AaBb) in pea, what is the probability of offsprings to have a pure homozygous dominant genotype for the first trait, and heterozygous for the second trait.

Answer 1

Answer:

• There are four possible combinations of gametes for the AaBb parent.

• Half of the gametes get a dominant A and a dominant B allele; the other half of the gametes get a recessive a and a recessive b allele.

• Both parents produce 25% each of AB, Ab, aB, and ab.