Biology, asked by Ajinas6911, 11 months ago

In a dihybrid cross between RRYY and rryy
parents, the number of RrYy genotypes in F₂ generation
(a) 4 (b) 3
(c) 2 (d) 1

Answers

Answered by Nandininoopur
1

Answer:

b

Explanation:

correct correct answer is b it means three I hope you like it

Answered by laraibmukhtar55
0

Number of genotype in F2 generation:

• Option “A” is correct i.e. 4.

• In a dihybrid cross between RRYY and rryy parents, the number of RrYy genotypes possible in F2 generation will be 4.

• This could be considered by using Punnet square.

Given Genotype: RRYY X rryy

Given Gametes: RY ry

products of F1 Generation: RrYy

Selfing of F1

Given Genotype: RrYy X RrYy

Given Gametes: RY, Ry, rY and ry X RY, Ry, rY and ry

products of F2 Generation:

RRYY RRYy RrYY RrYy

RRYy RRyy RrYy Rryy

RrYY RrYy rrYY rrYy

RrYy Rryy rrYy rryy

• Thus, it is clear that RrYy happens 4 times in F2 generation.

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