In a dihybrid cross between RRYY and rryy
parents, the number of RrYy genotypes in F₂ generation
(a) 4 (b) 3
(c) 2 (d) 1
Answers
Answered by
1
Answer:
b
Explanation:
correct correct answer is b it means three I hope you like it
Answered by
0
Number of genotype in F2 generation:
• Option “A” is correct i.e. 4.
• In a dihybrid cross between RRYY and rryy parents, the number of RrYy genotypes possible in F2 generation will be 4.
• This could be considered by using Punnet square.
Given Genotype: RRYY X rryy
Given Gametes: RY ry
products of F1 Generation: RrYy
Selfing of F1
Given Genotype: RrYy X RrYy
Given Gametes: RY, Ry, rY and ry X RY, Ry, rY and ry
products of F2 Generation:
RRYY RRYy RrYY RrYy
RRYy RRyy RrYy Rryy
RrYY RrYy rrYY rrYy
RrYy Rryy rrYy rryy
• Thus, it is clear that RrYy happens 4 times in F2 generation.
Similar questions